8^(2)+1=2(x-5)

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Solution for 8^(2)+1=2(x-5) equation: 



8^(2)+1=2(x-5)

We move all terms to the left:

8^(2)+1-(2(x-5))=0

We add all the numbers together, and all the variables

-(2(x-5))+65=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

-2x+10+65=0

We add all the numbers together, and all the variables

-2x+75=0

We move all terms containing x to the left, all other terms to the right

-2x=-75

x=-75/-2

x=37+1/2

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